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BASIC BUILDING CONCEPTS
Circuit: A closed conducting loop in which electric current flows continuously is called an electric circuit or simple circuit.
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If net charge ‘q’ flows across any cross-sectional area in a time ‘t’, then the current flows through the conductor is
The SI unit of current is ampere(A). Flow of one coulomb of charge per second is called one ampere, i.e.
1 A = 1 coulomb per second
Small units of current are 1 mA =10 -3 A (mA = milliampere) 1 μA =10 -6 A (pA = microampere)
Direction of current: The charge carriers in metallic conductor are free electrons. The motion of these free electrons in a particular direction constitutes an electric current. Conventionally, the direction of electric current is taken as opposite to the direction of the flow of electrons. In an electric circuit, the direction of conventional current is always taken from the positive terminal of the cell/battery through the various components and then to the negative terminal.
Potential: The work done in bringing a unit positive charge from infinity to a point in an electric field is called potential at that point.
Potential difference: The potential difference between two points in an electric field or across the ends of a conductor is equal to the work done in bringing a charge from one point to another. If W is the work done in bringing a charge q from one point to another, then the potential difference between these two points is given by
V=Work Done (W)/Charge(q)
The unit of work done is joule and that of charge is coulomb. Therefore, the unit of potential difference is volt (V).
1 volt=1 joule(J)/1 coulomb(C) or 1V = 1 JC -1
Resistance: It is the characteristic property of a conducting wire which resists the flow of electric current through it. From Ohm’s law, V = IR or R = V/I Thus, the ratio of potential difference to the current flowing through the conductor is equal to the resistance of the conductor. The flow of electrons is retarded by the resistance of the conductor. It is expressed in volt/ampere or ohm(Ω). One ohm is equal to the resistance of a conductor through which a current of one ampere flows when one volt potential difference is applied across its ends. The resistance of a conductor depends on its
1 Ω = 1 VA -1
DESCRIPTION OF APPARATUS USED
AIM To study the dependence of potential difference (V) across a resistor on the current (/) passing through it and determine its resistance. Also plot a graph between V and I.
MATERIALS REQUIRED Nichrome or manganin wire, ammeter, voltmeter, battery eliminator, rheostat, one-way plug key and connecting wires.
RESULT
PRECAUTIONS
SOURCE OF ERROR
INTERACTIVE SESSION
Question 1: Which basic law of electricity is verified by you from this experiment? Answer: Ohm’s law.
Question 2: State Ohm’s law. Answer: If physical conditions such as temperature, pressure etc., remain the same, the current flowing through the conductor is directly proportional to the potential difference applied across it.
Question 3: In which unit current is measured? Answer: It is measured in amperes.
Question 4: What are the most essential conditions for current flow through the conductor? Answer:
Question 5: Which physical quantity is represented by the ratio of ‘V and T? Answer: The ratio of V and I represents the resistance of the conductor,i. e. R = V/I Question 6: What is the SI unit of resistance? Answer: The SI unit of resistance is ohm (Ω). 1Ω=1 volt/ampere.
Question 7: Why is it advised that never allow the current to flow for a long time in a resistance wire? Answer: To avoid heating effect of current. As per Joule’s law of heating effect, (H = I2Rt) the wire will be heated up which leads to increase its resistance.
Question 8: What do you mean by resistance of a conductor? Answer: The obstruction offered by the conductor to the flow of electric current through it is called resistance.
Question 9: On what factors, does the resistance of wire depend? Answer:
Question 10: What is least count? Answer: The least quantity that can be measured accurately by any instrument is called its least count.
Question 11: What is zero error? Answer: If the pointer of the meter (ammeter/voltmeter) does not coincide with zero of the scale, i.e., it reads a little more or less when the circuit is open, this type of error in reading of the scale is called zero error. It is always substracted from the observed reading. Question 12: There are two wires, thick and thin. Which one will have greater resistance? Answer: Thin wire as R ∝ l/A
Question 13: Give the composition of nichrome alloy. Answer: 68% Ni, 15% Cr, 15.5% Fe, 1.5% Mn. *
Question 14: What is a battery eliminator? Answer: It is used in place of cell/battery. With the help of step down transformer higher voltage of an alternating current is converted into low voltage and then converted into the direct current with the help of a rectifier.
Question 15: Why does the current not flow in the circuit when we take out the plug from key? Answer: The air present in the gap is the bad conductor of electricity. So, the circuit breaks.
NCERT LAB MANUAL QUESTIONS
Question 1: In this experiment, it is advised to take out the key from the plug when the observations are not being taken. Why? Answer: To avoid unnecessary heating of wire, it is advisable to take out the key from the plug when the observations are not being taken because current produces heating effect and the resistance increases with the increase in temperature.
Question 2: Suppose the ammeter (or voltmeter) you are using in this experiment does not have positive (+) and negative (-) terminal markings, how will you use such ammeter (or voltmeter) in the circuit? Answer: We will connect the ammeter or voltmeter arbitrary in the circuit and observe the deflection of the pointer. If the pointer strikes the stopper (i.e., before the zero reading of the scale) or deflection occurs in the opposite direction, then by interchanging the terminal connections, we can use these devices properly in the circuit.
Question 3: If the resistor of a known resistance value is replaced with a nichrome wire of say 10 cm length, how do the values of current through the nichrome wire and potential difference across the two ends of it change? How the values will change if the replaced wire is of manganin in place of nichrome? Answer: The resistivity of an alloy is generally higher than that of metals. Therefore, by replacing the known resistance value resistor with nichrome wire, the value of current through nichrome wire will decrease and potential difference across its two ends will increase. The resistivity of manganin wire is 44 x10 -8 Ωm while that of nichrome wire is 100 x10 -8 Ωm . So, manganin wire offers less resistance as compared to the nichrome wire for the same length and same arean of cross-section. Hence, the value of current through the manganm wire will increase and the potential difference across its ends will decrease.
Question 4: Suppose in this experiment you see that the deflection on ammeter (or voltmeter) scale goes beyond the full scale. What will you infer from such an observation? What will you infer if the deflection takes place in opposite direction? Answer: If the deflection on ammeter (or voltmeter) scale goes beyond the full scale, we can infer that
Question 5: Why is it advised to clean the ends of connecting wires before connecting them? Answer: To remove the insulating layer, if any, from the ends of the connecting wire.
PRACTICAL RASED QUESTIONS Multiple Choice Questions/VSA (1 Mark)
Question 2: Three students X, Y and Z, while performing the experiment to study the dependence of current on the potential difference across a resistor, connect the ammeter (A), the battery (B), the key (K) and the resistor (R) in series, in the following three different orders. X——>B, K, R, A, B Y ——> B, A, K, R, B Z ——> B, R, K, A, B Who has connected them in the correct order? (a) X (b) Y (c) Z (d) All of them
Question 4: A voltmeter has a least count of 0.05 volt. While doing Ohm’s law experiment, a student observed that the pointer of the voltmeter coincides with 15th division, the observed reading is (a) 0.75 V (6) 0.075 V (c) 7.5 V (d). 75 V
Question 5: In an experiment to study dependence of current on the potential difference across a given resistor, four students P, Q, R and S kept the plug key in the circuit closed for time t1 and then open
Question 6: The following ‘precautions’ were listed by a student in the experiment on study of ‘Dependence of current on potential difference’: [Delhi 2009] (A) Use copper wires as thin as possible for making connections. (B) All the connections should be kept tight. (C) The positive and negative terminals of the voltmeter and the ammeter should be correctly connected. (D) The ‘zero error’ in the ammeter and the voltmeter should be noted and taken into consideration while recording the measurements. (E) The ‘key’ in the circuit, once plugged in, should not be taken out till all the observations have been completed. The ‘precautions’ that need to be corrected and revised are (a) (A), (C) and (E) (b) (C) and (E) (c) (B) and (E) (d) (A) and (E)
Question 8: An ammeter has 20 divisions between mark 0 and mark 2 on its scale. The least count of the ammeter is (a) 0.02 A (6) 0.01 A (c) 0.2 A (d) 0.1 A
Question 9: In a voltmeter, there are 20 divisions between the 0 mark and 0.5 V mark. The least count of the voltmeter is (a) 0.020 V (6) 0.025 V (c) 0.050 V (d) 0.250 V
Question 12: Three students A, B and C carried out measurements of current and potential difference with the help of the ammeter and voltmeter, they did the following A: viewed the divisions from the left of the pointer B: viewed the divisions from the right of the pointer C: viewed the divisions directly above the pointer The correct procedure followed by the student (a) A (b) B (c) C (d) none of them
Question 13: The plane mirror is used in the meters is to (a) avoid the error of parallax (b) help to take more accurate observations (c) reflected light makes the scale illuminated (d) make the meter look good
(a) K (b) L (c) M (d) N
Short Answer Questions
Question 2: Name and state the law that connects the electric current flowing through a metallic resistor and potential difference across its two ends. State the condition under which it is valid.
Question 4: Mention the condition under which charges can move in a conductor. Name the device which is used to maintain this condition in an electric circuit for verifying Ohm’s law.
Multiple Choice Questions/VSA 1. (b) 2. (d) 3. (b) 4. (a) 5. (a) 6. (d) 7. (c) 8. (d) 9. (b) 10. (d) 11. (b) 12. (c) 13. (a) 14. (b) 15. (c)
2. Ohm’s Law: It states that the potential difference (V) across the ends of a given metallic conductor in an electric circuit is directly proportional to the current (I) flowing through it. Ohm’s law is valid only when the temperature of the conductor remains constant.
3. Using Ohm’s law, V= IR 3=I 3 I = 1 A Therefore, ammeter reading is 1 A. Voltmeter reading = Potential difference across 3 Q resistor V= IR = 1 3 = 3 V.
4. Electric potential should be maintained across the ends of a conductor to move the charge through it. Cell or battery is the device used to maintain the potential difference across the conductor.
Science Practical Skills Science Labs Math Labs Math Labs with Activity
Define a circuit diagram?
Define electric current. Give its SI unit?
Define 1 A of current?
What is the direction of current in a circuit?
How are ammeter and voltmeter connected in a circuit?
What is the ideal resistance of ammeter and voltmeter?
What is Rheostat?
State Ohms law?
What is battery eliminator?
What is the resistance of a ideal ammeter?
AIM To study the dependence of potential difference (V) across a resistor on the current (I) passing through it and determine Its resistance and also plotting a graph between V and I.
MATERIALS REQUIRED
Resistance wire, ammeter, voltmeter, battery eliminator, rheostat, One-way plug key, and connecting wires.
Ohm’s Law states that “If the physical conditions such as temperature, pressure, etc., remain the same during the experiment, then the current (I) flowing is directly proportional to the potential difference (V) across the ends of the circuit.”
Mathematically,
1. The resistance(R) is the characteristic property of the conductor which resist the flow of electric current through it.
2. The potential difference (V) is the is the potential difference across the ends of a conductor.
3. The electric current (I) is the amount of charge flowing through a particular area in a unit time.
If we plot a graph between the current (I) and the applied potential difference(V) between its ends, for an ideal resistance it will be a straight line as shown:
Circuit Diagram
In the above diagram
Apparatus Arrangement :
The actual diagram of the Ohm’s Law apparatus is shown here:
1. By using the circuit diagram or apparatus arrangement, we set up the circuit for finding the dependence of voltage on the current flowing in the circuit.
2. Clean the end of connecting wires using with sandpaper to remove the insulation.
3. Determine the least count of the ammeter and voltmeter and note them under observation section.
4. Check for any zero error in the ammeter and voltmeter and if any record it in table ‘A.’
5. Switch on the battery eliminator, plug the key and adjust the resistance offered by the rheostat by sliding its variable terminal till the ammeter and the voltmeter show a reading.
6. Write the readings of ammeter and voltmeter in the observation table. Take out the key plug out of the circuit to make the circuit open.
7. Repeat the process done in step 4 and 5 for the different values of current by varying the sliding terminal of the rheostat and note down the reading for a respective value of voltage for current in the observation table.
8. Note all the observations in the observation table ‘B’ and then find the ratio of - for each set of observations. Find the mean value of R.
9. Plot a graph by taking I along the y-axis and V along the x-axis.
Observations:
OBSERVATION TABLE
1. Least count of ammeter:
The image of the ammeter is attached here:
The range of the ammeter =500 - 0 mA = 500 mA = 0.5 A
The number of divisions in between two consecutive values= 10
2. Zero error of ammeter:
The needle of the ammeter points towards zero of the main scale of the ammeter.
3. Least count of voltmeter:
The range of voltmeter = 2 - 0 V= 2 V.
The number of division in small scale between two division on the main scale
4. Zero error of voltmeter = 0 V.
Table (B) for the reading of ammeter and voltmeter
CALCULATION
1. The ratio of V and I for each corrected set of observation is given in the table:
The mean value of Resistance is calculated as:
2. The graph between the potential difference ‘V’ along the x-axis and the current ‘F along the y-axis for I-Vgraph as shown or V’ on the y-axis and ‘I’ an x-axis is drawn:
3. Find the slope of the line.
(i) For I-V graph.
:. Resistance of nichrome (Or manganin) wire =1.97 Ω.
(ii) For the V-I graph,
wire = 2.06 Ω.
1. The linear nature of the I-V graph or V-I graph shows that potential difference across the end of the conductor is directly proportional to the current flowing through it, i.e., V ∝ I. This proves the Ohm’s law graphically.
2. The resistance of the wire obtained from the graph is equal to the mean calculated value of R. It also verifies the Ohm’s law.
3. The resistance of the given wire = 2.05 Ω.
PRECAUTIONS
1. The ends of connecting wire should be rubbed using sandpaper.
2. All connections should be kept clean and tight.
3. The positive terminal of ammeter or voltmeter should be connected to the positive terminal of the battery or battery eliminator.
4. The ends of the resistance wire must be connected across the terminals of the voltmeter.
5. Remove the key out of the circuit when not in use to avoid the heating effect of the circuit.
The circuit diagram is a schematic representation which shows the arrangement of different devices or components by using their electrical symbol is called a circuit diagram.
The basic circuit diagram is given as:
Electric current: It is the amount of charge following through a particular area in a unit time is called an electric current.
The SI unit of current is 1A.
The 1A of current is the flow of 1 coulomb of charge per second.
What is mA and μA?
Ampere is the standard unit of current. The small units of current are:
1. Milli-Ampere: 1 mA = 10 -3 A
2. Micro-Ampere: 1Μa = 10 -6 A
The conventional direction of current is taken from positive terminal of the battery through the various circuit components & then to negative terminal.
What are the functions of the following components of electric circuit? i. Ammeter ii. Voltmeter iii. Resistor iv. Switch v. Battery
The functions of the components are given as:
i. Ammeter: It is a measuring instrument used to measure the current in a circuit.
ii. Voltmeter: A voltmeter is an instrument used for measuring electrical potential difference between two points in an electric circuit
iii. Resistor: It is an electrical component that limits or regulates the flow of electrical current in an electronic circuit.
iv. Switch: A device for making and breaking the connection in an electric circuit.
v. Battery: A battery is an electrochemical cell that can be charged electrically to provide a static potential for power.
What is the difference between electric potential & electric potential difference?
i. The work done in bringing a unit positive charge from infinity to a point in an electric field is called as Electric potential of a point.
ii. The potential difference between two points in an electric field or across the ends of a conductor is equal to the work done in bringing a charge from one point to another
What is resistance and factors affecting the resistance of a body?
Resistance: It is the characteristic property of a conducting wire which resists the flow of electric current through it. Its SI unit is ohms.
The factor affecting the resistance of a body are:
1. Length of the wire.
2. Cross-sectional area.
3. The material of the conductor.
4. The temperature of the conductor.
What is the difference between voltmeter & ammeter?
Voltmeter is a very high resistance device which is used to measure the potential difference between two points. It is connected in parallel combination with the resistance across which the voltage drop has to be found.
It is a very low resistance device which is used to measure the strength of the current in a circuit, it is always connected in series in a circuit.
The ideal resistance of voltmeter is infinite ohms.
The ideal resistance of ammeter is 0 ohms.
If the physical conditions such as temperature, pressure remain the same, the current flowing through a conductor is directly proportional to the potential difference applied across it. Mathematically, V = IR
Where V is the potential difference I is the current
R is the resistance
Why it is never advised to keep the current flow for a long time in a resistance wire?
The flowing current in the circuit led to the heating effect of current. As per joule law H = I 2 RT, the wire will be heated up which increases the resistance of wire.
What is an essential condition for current flow through the conductor?
The necessary condition are:
1. The circuit must be closed.
2. There must be a source of electrical energy.
Why does current not flow in the circuit when we take out the plug from the key?
Where there is no connectivity in the medium, the current does not flow. The air present in the gap caused due to removal of plug from the key is the bad conductor of electricity. Hence, the current does no flow.
It is used in place of cell/ battery. With the help of step down transformer higher voltage of an alternating current is converted into a low voltage and then converted into direct current with the help of a rectifier.
How do you mean by slope of a graph? What is the formula for slope?
The slope is a measure of the steepness of any line connecting two points.
For a line connecting any two points say P(x 1 , y 1 ) and Q (x 2 , y 2 ), the slope is given as :
The resistance of an ideal ammeter is zero.
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There is no mode of learning better than learning from practical knowledge and that is why CBSE has prescribed students the Lab Manual of Class 10 Physics Ohm’s Law. Students looking for an individual file of Ohm’s Law Physics Lab Manual Class 10 can use the link we have provided here on this page.
Interestingly, the PDF file not only contains the process to perform an activity on the Ohm’s Law but helps students prepare for the internal assessment and Viva examination.
Inside the Ohm’s Law Lab Manual Class 10 PDF, there are various helpful and important things for students - Discussed below in detail:
Always choose a trustworthy platform to download study materials such as Selfstudys.com. If you want to download the PDF file of Ohm’s Law from Selfstudys then follow the steps given below:
From helping students perform the practical activity to preparing for the annual Viva examination, the Class 10 Ohm’s Law Lab Manual plays a significant role in a student’s academic session. Here are some of the key significant roles:
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Learn all about Ohm's law
Today you’ll learn a step by step guide to perform the Ohm’s law Experiment . You’ll learn the use of voltmeter and ammeter in parallel and series, resistors, dc power supply, wires and all other equipment which is used in doing the practical.
This article demonstrates the Ohm’s Practical experiment. You can find the lab report, reading, observations, and theory here .
Let’s start with the circuit diagram :
The graphic below illustrates a visual representation of steps:
Carbon resistors are the most popular type of resistors which are used in lab experiments. Circular color bands are used on their bodies are to indicate the amount of resistance they possess. We can use a color coding chart to find the value of carbon resistors. Let’s consider your resistor box has three resistors.
Resistor 1 is a 4 Band Resistor with Brown, Black, Red, Gold bands on it.
Resistor 2 has Red, Red, Red, Gold bands on it.
Resistor 3 has Red, Red, Orange, Gold bands on it.
The first band of all resistors is the first digit of resistance, the second band is the second digit of resistance. The third band indicates the multiplier values whereas the fourth band indicates the tolerance value of resistors.
Let’s understand how a color coding chart helps us to find the value of resistance.
Let’s decode our first resistor:
Here the first band is brown so the first digit is 1, the second band is black so second digital 0, the third red band provides 100 as multiplier which is 10 * 100 = 1000 Ω. The last golden band represents a tolerance of 1 kΩ ± 5%.
The second and third resistors are decoded to be 2.2 kΩ ± 5% and 22 kΩ ± 5%.
A variable dc power supply or VDC has a circular knob which can be rotated to obtain variable voltages. An LCD displays the number of selected output voltages. The alligator wires are used to take the output from the supply. Always connected red wire/probe to red (live) terminal of the battery and black wire to the black terminal of the battery. The figure below displays a variable dc power supply. While performing the experiment you rotate the knob to obtain step by step variable voltages.
A Voltmeter is connected to the resistor for measuring the amount of potential difference across its ends. A voltmeter always connects in parallel because the potential difference remains same in parallel. Practically voltmeter, ammeter, and ohmmeter are designed together in the form of the multimeter. So you need to set your multimeter to the voltage scale.
An ammeter is a current measuring device. It connects in series to the circuit under measurement.
We know that resistance is a measure of the opposition to the flow of electricity in a circuit. The potential difference helps to understand the amount of energy transferred between two points in a circuit. In this session, let us learn to determine the resistance per cm of a given wire by plotting a graph for potential difference versus current.
To determine the resistance per cm of a given wire by plotting a graph for potential difference versus current.
According to Ohm’s law, the electric current flowing through a conductor is directly proportional to the potential difference across its ends, provided the physical state (pressure, temperature, and dimensions) of the conductor remains unchanged.
If I is the current flowing through the conductor and V is the potential difference across its end, then
Where R is the constant of proportionality and is termed as the electrical resistance of the conductor. Resistance R depends on the dimensions and material of the conductor. The relationship between the resistance of a material and its length and area of the cross-section is given by the formula
Where ρ is the specific resistance or resistivity and is a characteristic of the material of the wire.
Range of ammeters = _____ mA to _____ mA
The least count of ammeter = _____ mA
Range of voltmeter = _____ V to ____ V
The least count of voltmeter = _____ V
The least count of meter-scale = _____ m
Length of the given wire, l = _____ m
) | ) | |
2. Determine the slope of the graph. The resistance of the given wire is then equal to the reciprocal of the slope.
From the graph, R = BC / AB = _____ Ω
3. Resistance per unit length of the wire = R/t = _____ Ωm –1
Here, R is the resistance per unit length and Δ R is the estimated error. Δ V and Δ I are the least count of voltmeter and ammeter respectively.
The potential difference across the wire varies linearly with the current.
The resistance per unit length of the wire is ( R ± Δ R ) = _____ ± _____ Ωm –1 ).
1. State Ohm’s Law.
Ohm’s law states that the potential difference across an ideal conductor is proportional to the current through it. The constant of proportional is known as the resistance R . Ohm’s law is given by V = IR .
2. Which are the factors on which the resistance of a conductor depends on?
The resistance of a conductor depends on the following factors:
3. What is a rheostat?
A rheostat is a variable resistance that is used to control the current.
4. What is the shape of a V vs I graph for a linear resistor?
The shape of the V vs I graph for a linear resistor is a straight line.
5. What is the reciprocal of resistivity called?
The reciprocal of resistivity is called conductivity.
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NCERT Class 10 Science Lab Manual - Ohm's Law. Experiment To Verify Ohm's Law Class 10 CBSE. Ohm's Law Experiment Class 10 Pdf Introduction. Charge: There are two charges in nature i.e., positive and negative. The negative charge is due to electron. Its value is 1.6 x 10 -19 C. It is measured in coulombs.
The values of Current (I) flowing through a conductor for the corresponding values of potential difference (V) are given. Plot a graph between V and I. From the above table. We can see that, the ratio of 𝑉/𝐼 is always constant. This gives resistance. The resistance is 25 in above case. Q2. The values of Current (I) flowing through a ...
Then a graph is needed to plot the current along the positive Y-axis and the potential difference along the positive X-axis. Ohm's Law can be verified by finding the Voltage to current ratio. If the ratio remains constant [equation- (1)] for all sets of data, then we can say that the voltage across the resistance is proportional to the ...
CBSE Class 10 Science Lab Manual - Ohm's Law. To study the dependence of potential difference (V) across a resistor on the current (I) passing through it and determine its resistance (R). Also plot a graph between V and I. A voltmeter and ammeter of suitable range, resistance wire or resistor, some connecting wires, a key, a dry cell (or ...
Calculations [Verification of Ohm's law report] The theoretical calculations are achieved from the original formula, V = IR. You can also verify them from the basic Ohm's law calculator. Graph for Ohm's Law Lab report. The real (practically calculated - red color) vs the theoretical values (blue) are plotted on the graph.
Question of Class 10-Ohm's Law : Ohm's Law: The flow of electric current through a conductor depends on the potential difference across its ends. ... Analyse the observations. Thus, we come to a conclusion that current through an electric component depends upon its resistance. ... Experiment to show that resistance of a conductor depends on ...
Record the observations in the observation table. Using the formula R=V/I, calculate the resistance. ... With the help of the graph between V and I, Ohm's law is verified as the plot is a straight line. Precautions. ... Physics Experiments Class 10 Viva Questions and Answers.
One of the most common tasks you can face in the 10th-grade physics or science laboratory is to perform the Ohm's Law Experiment. It is common in class IX or class X in most boards like CBSE, ICSE, state boards, and even in IGCSE or IB curriculums. This experiment is also there for certain class 12 syllabus. Ohm's Law Experiment Lab Setup
Ohm's Law Solved Problems. Example 1: If the resistance of an electric iron is 50 Ω and a current of 3.2 A flows through the resistance. Find the voltage between two points. Solution: If we are asked to calculate the value of voltage with the value of current and resistance, then cover V in the triangle.
CBSE Class 10 Science Lab Manual - Ohms Law - Free download as PDF File (.pdf), Text File (.txt) or view presentation slides online. 1. The document describes an experiment to verify Ohm's law by plotting a graph of potential difference (V) versus current (I) for a resistor. Various electrical components like a voltmeter, ammeter, resistor, battery and rheostat are connected in a circuit.
Theory: The experiment requires four cells of 1.5 V, 0.5 m coil of nichrome wire, key, ammeter, and voltmeter. Nichrome is an alloy of nickel, chromium, manganese, and iron metals. Experimental set-up. Connect the cell, nichrome wire, ammeter and key in series, and the voltmeter parallel to the circuit. First, connect only one cell in the circuit.
Extra Questions for Class 10 English First Flight Expand / Collapse. ... While doing Ohm's law experiment, a student observed that the pointer of the voltmeter coincides with 15th division, the observed reading is ... The value of resistance in the other four observations will be. 2. Ohm's Law: It states that the potential difference (V ...
1. The ratio of V and I for each corrected set of observation is given in the table: The mean value of Resistance is calculated as: =2.046 Ω ~ 2.05Ω. 2. The graph between the potential difference 'V' along the x-axis and the current 'F along the y-axis for I-Vgraph as shown or V' on the y-axis and 'I' an x-axis is drawn:
Join Telegram For Exclusive Content. CBSE Class 10 Lab Manual Chapter 1 Ohm's Law Download here in pdf format. These Lab Manual may be freely downloadable and used as a reference book. Learning does not mean only gaining knowledge about facts and principles rather it is a path which is informed by scientific truths, verified experimentally.
Precautions: One of the crucial things while conducting the activity given in Class 10 Ohm's Law lab manual is to take precautions to avoid making mistakes or getting hurt. The precautions section in the lab manual explains students to what to not do during the activity of Ohm's Law. Source of Error: The PDF that we provide contains, the ...
Steps to execute Ohm's law experiment. 1> We have to start the test with a single cell. We have to connect the circuit as shown in Figure a. - The ammeter will show us the current I flowing through the circuit, and the voltmeter will measure the potential difference V between the ends A and B of the wire.
Ohm performed repeated experiments on a resistor, applied different voltages, measured current and found relationship between these quantities. He finally published the law in 1827 and generalized his observations in single statement: The current flowing through the resistor is directly proportional to the voltage applied across it.
Activity 12.1 https://youtu.be/mnIj_1lUARc Activity 12.2 https://youtu.be/QnVUxfE0_tY Activity 12.3 https://youtu.be/mC4jatgAxxE Activity 12.4 https://youtu....
There are various ways to prove that resistors obey Ohm's law (V=IR). Ohm's law says that voltage across a component is proportional to the current going thr...
Calculations. Plot a graph between the potential difference across the wire V and the current I flowing through the wire as shown below. 2. Determine the slope of the graph. The resistance of the given wire is then equal to the reciprocal of the slope. From the graph, R = BC / AB = _____ Ω. 3.
Fig. E 1.2. Note whether pointers in milliammeter and voltmeter coincide with the zero mark on the measuring scale. If it is not so, adjust the pointer to coincide with the zero mark by adjusting the screw provided near the base of the needle using a screw driver. Note the range and least count of the given voltmeter and milliammeter.
The symbol for ohm or unit is Ω, and this is representing the resistance. Now, in order to comprehend Ohm's Law is to imagine like a liquid circuit, we have our pump (battery; voltage), then it is flowing and meets it's resistance. This is the important part of Ohm's law and the resistance, is that if the resistance is bigger, then less ...